But real-world lists aren’t always so simple. And for certain data, a simple consecutive list just won’t do. Sometimes we receive spreadsheets that have some type of intrinsic grouping but no unique group identifier. The challenge is that we would really like to apply Pivot Tables to this data, but we can’t do anything until there exists some type of group identifier.

**Problem #1: Items grouped without collation**

Take a look at the datasheet below from my nonexistent accounting information system.

Because I’m smart(ish), I know that a new group begins every third row of data. The first three rows of data (Excel rows 2,3, and 4) represent store 1, the next three store 2, and so forth. I would like to add an additional group_id column such that each grouping is numbered consecutively. Something like this:

*integer division*in the amount of each item in a group to the current row.

*So, for row 3, we have*

=INT((ROW()-2)/3) -> =INT((3-2)/3) – > =INT(1/3) -> = INT(0.33) = 0.

For Items Grouped Without Collation

=INT

((ROW()-First row of data on spreadsheet) /# Items per Group)[+1]optional

**Problem #2: Items grouped with collation**

In the following spreadsheet, we’ve culled information from many different spreadsheets maintained by many different people.

The problem is that each spreadsheet administrator used a different naming convention for the same account (see the highlighted accounts). And take a look at the final Retained Earnings and note that it is labeled ” RE.” Those extra spaces can creep into the spreadsheet and easily go unnoticed. *What a nightmare.*

But wait, our list has some semblance of order: accounts can be grouped every sixth row. We just need to group each item, one through five, until the end of the list. Like so,

How? With this formula,

This should look familiar to the one above. But instead of using integer division, we’re now using *modulo division*; that is, we’re interested in the *remainder*. Take row 3

=MOD(ROW()-2, 5)+1 -> =MOD(3-2, 5)+1 – > =MOD(1, 5)+1 -> = 1+1 =2.

Here’s the cheat sheet:

For Items Grouped With Collation

=MOD

((ROW()-First row of data on spreadsheet,# Items per Group)[+1]optional

**Final Thoughts**

1. Once you’ve created your new group_id column, it’s a good idea to select your new work, copy, and then paste as values. If the groupings aren’t going to change later, there’s no reason to keep it as a formula. Remember, fewer formulas means better Excel performance — especially if you plan to use a Pivot Table later.

2. If you’re not into the numbering scheme, create a lookup table that maps the numbers to a proper name. Create another column at the front of your data and use a lookup method, like Index, to map the correct names. Then do a copy/paste values.

3. If you have a list scheme you use quite often, you can actually save it as a custom fill series and then use it later.

**Remember:**

For Items Grouped Without Collation

=INT

((ROW()-First row of data on spreadsheet) /# Items per Group)[+1]optional

For Items Grouped With Collation

=MOD

((ROW()-First row of data on spreadsheet,# Items per Group)[+1]optional

MartínGreat, love using that kind of formulae !!There's an easier way, however, to fill that gap, assuming always that there is a sequence. you just type in the first set of the sequence, select them, double click on the black cross on the bottom right to expand the selection to the rest of the list, and when prompted for the filling method, select copy series (XL 2003).

JordanTrue – but it's way less fun. 😉